(2x^2+3x+1)(x+1)=0

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Solution for (2x^2+3x+1)(x+1)=0 equation:


Simplifying
(2x2 + 3x + 1)(x + 1) = 0

Reorder the terms:
(1 + 3x + 2x2)(x + 1) = 0

Reorder the terms:
(1 + 3x + 2x2)(1 + x) = 0

Multiply (1 + 3x + 2x2) * (1 + x)
(1(1 + x) + 3x * (1 + x) + 2x2 * (1 + x)) = 0
((1 * 1 + x * 1) + 3x * (1 + x) + 2x2 * (1 + x)) = 0
((1 + 1x) + 3x * (1 + x) + 2x2 * (1 + x)) = 0
(1 + 1x + (1 * 3x + x * 3x) + 2x2 * (1 + x)) = 0
(1 + 1x + (3x + 3x2) + 2x2 * (1 + x)) = 0
(1 + 1x + 3x + 3x2 + (1 * 2x2 + x * 2x2)) = 0
(1 + 1x + 3x + 3x2 + (2x2 + 2x3)) = 0

Combine like terms: 1x + 3x = 4x
(1 + 4x + 3x2 + 2x2 + 2x3) = 0

Combine like terms: 3x2 + 2x2 = 5x2
(1 + 4x + 5x2 + 2x3) = 0

Solving
1 + 4x + 5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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